X=width of the lake
y=length of the lake.
we set out this system of equiations
x*y=9/20
x=y/5
we solve by sustitution method
(y/5)*y=9/20
y²/5=9/20
y²=(5*9)/ 20
y²=2.25
y=√2.25=1.5
x=y/5
x=1.5/5=0.3
Solution:
width of the lake=0.3 miles
lenght of the lake=1.5 miles
<h2>Answer:</h2><h2>15/4y²</h2><h2>Steps:</h2>
5y^2×3/4
calculate:
15/4y^2
alternate form:
3.75y²
Answer:
her first mistake was on line 3.
line 1: 80 + [2(3 1/2 + 1 1/2)]
line 2: 80 + [2(5)]
line 3: 80 + 10
line 4: 90
Step-by-step explanation:
on line 3 she added 80 + 2, but she should have multiplied 2 by 5. the correct steps would be:
line 1: 80 + [2(3 1/2 + 1 1/2)]
line 2: 80 + [2(5)]
line 3: 80 + 10
line 4: 90
3+6x+3x+ 6 = 180
9x + 9 = 180
9x = 171
x = 19
Answer:
A^(2) + B^(2) = C^(2)?????????????
Step-by-step explanation:
that's an isosceles triangle, not a right-angle triangle
