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tatuchka [14]
2 years ago
8

The area of circle B is 121 times greater than the area of circle A. The radius of circle B is 44. What is the radius of circle

A?
A) 2.75

B) 4

C) 44

D) 88
Mathematics
1 answer:
xxMikexx [17]2 years ago
5 0
<em>Formula:</em>
\bigg( \dfrac{radius_1}{radius_2} \bigg)^2 =  \dfrac{area_1}{area_2}

<em>Plug in the values:</em>
\bigg( \dfrac{r}{44} \bigg)^2 = \dfrac{1}{121}

<em>Simplify LHS:</em>
\dfrac{r^2}{1936}  = \dfrac{1}{121}

<em>Multiply by 1936 on both sides:</em>
r^2  = \dfrac{1936}{121}&#10;

<em>Simplify RHS:</em>
r^2 = 16

<em>Square root both sides:</em>
r = 4

Answer: The radius is 4 units. (Answer B)
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Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
Use the function below to find F(3)<br> F(x) = (1/6)^x
alukav5142 [94]

Answer: 1/216

Step-by-step explanation: please mark me brainly

7 0
2 years ago
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PLEASE HELP I WILL GIVE BRAINLYEST AWNSER IF YOU AWNSER ALL THE PROBLEMS IN ALL THE QUESTION
bixtya [17]

Answer:

7) Mean = 48               8)  Mean = 59.6          9)  Mean = 31.6     10)  Mean = 42.1

   Median = 47.5              Median = 61                Median = 32           Median = 40

   Mode = 72                    Mode = 90                  Mode = 46             Mode = 51

   Range = 66                  Range = 79                 Range = 34            Range = 51

Step-by-step explanation:

7 0
3 years ago
Simply please “picture”
oksian1 [2.3K]
<h3>Answer: (-infinity, 7]</h3>

=====================================

Explanation:

The first interval (-infinity, 3) describes any number less than 3, so we can write x < 3 in short hand (where x is the unknown number).

The second interval (-1, 7] means we start at -1 and stop at 7. We do not include -1 but include 7. So we say that -1 < x \le 7 (ie x is between -1 and 7; exclude -1, include 7)

If you were to graph each ona number line, you would see that the too intervals have overlapping parts. The right most edge extends out as far as x = 7. There is no left most edge as it goes onforever that direction.

Therefore, the to intervals combine to get x \le 7 which turns into the interval notation answer of (-infinity, 7]

-----------

It might help to think of it like this: x < 3 and -1 < x \le 7 say "x is some number that is less than 3, or it is between -1 and 7". So x could be anything less than 7, including 7 itself.

4 0
3 years ago
Use the given x and y values to write a direct variation<br> equation.<br> x = 2, y = 30
exis [7]

Answer:

y = 15x

Step-by-step explanation:

Given x and y are in direct variation then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 2, y = 30, then

30 = 2k ( divide both sides by 2 )

15 = k

y = 15x ← equation of variation

5 0
2 years ago
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