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saul85 [17]
3 years ago
8

How many cubes would you use to make the structure above/below

Mathematics
2 answers:
loris [4]3 years ago
8 0
The answer is 17 cubes.
I drew lines to make cubes so I could see it better 
jonny [76]3 years ago
5 0

We are given a diagram.

We need to find the number of cubes would we use to make the given structure.

In order to find the number of cubes, we need to find the length, width and height of the given structure.

For the given structure, length = 4 units.

Width = 3 units and

Height = 2 units.

Length × width × Height = 4 × 3 × 2 = 24 cubes.

Now, subtracting missing number of cubes.

Missing number of cubes = 2+5 = 7.

Reamining number of cubes =24 -7 = 17 cubes.

<h3>Therefore, correct answer is 17 cubes.</h3>
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The graph of the function f(x) = –(x + 6)(x + 2) is shown below.
schepotkina [342]

Answer:

a. The function is increasing for all real values of x where  x < –4.

Step-by-step explanation:

Let me help you, I have answered this question once in Brainly as well

Given the factored form of the function:

f(x) = -(x + 6)(x+2)

<=> f(x) = -x^{2} - 8x -12

We will convert to vertex form

f(x) = -(x+4)^{2} + 4

Let analyse other possible answers:

<u>a. The function is increasing for all real values of x where  x < –4.</u>

True, because  the parameter a = - 1 so the graph open down all over its domain

<u>b. The function is increasing for all real values of x where  –6 < x < –2.</u>

Wrong, the function decrease in the interval from –4.< x < -2

<u>c. The function is decreasing for all real values of x where  x < –6 and where x > –2.</u>

Wrong, the function increase in the interval from -6 < x < -4

<u>d. The function is decreasing for all real values of x where  x < –4.</u>

Wrong,  The function is increasing  for all real values of x where  x < –4.

7 0
3 years ago
Read 2 more answers
A farmer water 3/8 of a field what percentage is equivalent to the fraction of the field the farmer wanted?
Aleks [24]
I believe the correct answer is: 37%
4 0
3 years ago
Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

  • all angles of the quadrilateral XAYB are right angles
  • all sides of XAYB are congruent and equal to 6 + 8 = 14 units.

Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

3 0
3 years ago
What is the value of x in the product of powers below?
Luda [366]
-7
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7 0
4 years ago
Expand and simplify (2c+1)(2c+3)
Mandarinka [93]
The answer would be 4c^2+8c+3

The arrow stands for squared off you didn’t already know but these are very easy to solve because you just multiply it out
6 0
2 years ago
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