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4 years ago

Which math problem is being modeled on the number line

Mathematics

1 answer:

REY [17]4 years ago

7 0

Well, both variables appear to be negative, and the only option present that equals -20 is option A

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The formula for the volume V of a rectangular prism is V = ℓwh, where ℓ represents the length, w represents the width, and h rep

Daniel [21]

Answer:

w = $\frac{V}{lh}$

Step-by-step explanation:

We can find the formula for the width by isolating w:

V = lwh

Divide each side by lh to isolate w:

$\frac{V}{lh}$ = w

8 0

3 years ago

Find the sine of both angle A and angle B.

olchik [2.2K]

Sin = opposite/hyp

Sin A = 10/26 = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps

6 0

4 years ago

Read 2 more answers

A cylinder is 20 inches long and has a diameter of 10 inches. What is the approximate volume of the cylinder? Use 3.14 for

Nastasia [14]

Answer:

1571in^3

Step-by-step explanation:

Given data

h= 20 in

d= 10 in

r= 10/2= 5 in

V= πr^2h

substitute

V= 3.142*5^2*20

V=3.142*25*20

V=1571 in^3

Hence the volume is 1571in^3

7 0

3 years ago

There are three scoring areas in an outdoor game, 5 points, 10 points and 25 points. What is the total number of point a player

sammy [17]

5(4) is 20. 10(8) is 80. 25(3) is 75. 20+80+75 equals 175. He has a total score of 175.

8 0

3 years ago

Read 2 more answers

Please answer the question below (ABOUT VECTORS AND MAGNITUDE)

coldgirl [10]

(a) v appears to have a fixed direction along the positive x-axis. If ||u|| = 150 N, ||v|| = 220 N, then when θ = 30°, you have

u = (150 N) (cos(30°) i + sin(30°) j ) ≈ (129.904 i + 75 j ) N

v = (220 N) (cos(0°) i + sin(0°) j ) = (220 i ) N

(i and j are the unit vectors in the positive x and y directions)

and their sum is

u + v ≈ (349.904 i + 75 j ) N

with magnitude

||u + v|| ≈ √((349.904)² + (75)²) N ≈ 357.851 N ≈ 357.9 N

and at angle φ made with the positive x-axis such that

tan(φ) ≈ (75 N) / (349.904 N) → φ ≈ 12.098° ≈ 12.1°

(b) Letting θ vary from 0° to 180° would make v a function of θ :

u = (150 N) (cos(θ) i + sin(θ) j ) = (150 cos(θ) i + 150 sin(θ) j ) N

Then

u + v = ((220 + 150 cos(θ)) i + (150 sin(θ)) j ) N

→ M = ||u + v|| = √((220 + 150 cos(θ))² + (150 sin(θ))²) N

M = √(48,400 + 66,000 cos(θ) + 22,500 cos²(θ) + 22,500 sin²(θ)) N

M = 10 √(709 + 660 cos(θ)) N

(c) As a function of θ, u + v makes an angle α with the positive x-axis such that

tan(α) = (150 sin(θ) / (220 + 150 cos(θ))

→ α = tan⁻¹((15 sin(θ) / (22 + 15 cos(θ)))

(d) Filling in the table is just a matter of evaluating M and α for each of the given angles θ. For example, when θ = 0°,

M = 10 √(709 + 660 cos(0°)) N = 370 N

α = tan⁻¹((15 sin(0°) / (22 + 15 cos(0°))) = 0°

When θ = 30°, you get the same result as in part (a).

When θ = 60°,

M = 10 √(709 + 660 cos(60°)) N ≈ 323.3 N

α = tan⁻¹((15 sin(60°) / (22 + 15 cos(60°))) = 23.8°

and so on.

4 0

3 years ago