The answer is: Each bag of flour weighs 1,32 kg.
If we the total weight of the bags is given, and we know both the number of bags of flour and sugar, and we also know the weight of each bag of sugar, then we have to find the unknown, which is X. 30 times X plus 4 times the weight of a bag of sugar would equal 42.6kg. Next step is to put the unknown on one side and the known values on the other side. We have 30 times X equals 42.6 minus 4 times 0.75.
To find X we need to divide the value with 30, or to sum up
30X + 4*0.75 = 42.6
30X + 3 = 42.6
X = (42.6 - 3) / 30
X = 1.32 kg
Answer:
6/8 and 9/12
Step-by-step explanation:
You can find any by multiplying numerator and denominator by any given number. The number multiplied has to be the same for the top and the bottom
1. Number is 2
3/4 * 2/2 = 6/8 (3*2 = 6 and 4*2 = 8)
2. Number is 3
3/4*3/3 = 9/12 (3*3 = 9 and 3*4 = 12)
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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3-4x=-6x^2
+6x^2=+6x^2
_____________
6x^2+3-4x=0
6x^2-4x+3=0
(-4)^2-4(6)(3)
16-72
Final Answer: -56
I need -487 time to regroup.
i did 426 - 913 = -487
