Answer:
a) 99.93%
b) 99.98%
Explanation:
Given that:
Total population size was only around 18 individuals ( for black-footed ferret)
If the annual survival rate in the wild was 0.4%.
a)
What is the probability that all 18 would have died in a single year?
To find that; we multiply the annual survival rate in the wild with the total population; which is:
(0.4%×18) = 0.072%
Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.
= (100.00% - 0.072%)
= 99.93%
b)
What is the probability that all 18 would have died in a single year if canine distemper was present?
Given that;
Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.
To determine the probability; we have:
1 - Annual mortality rate = annual survival rate
1 - 0.89 = 0.11 %
Therefore, 0.11% of 18 individuals = (0.0011 × 18)
= 0.0198%
Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate
= (100 - 0.0198)%
= 99.98%
Polar bears are listed in red as they are belong to Endangered Species. These species are gonna extincting due to gradual changes by environmental factors.
The attraction that holds two covalently bonded atoms together is called covalent bond
The pleural cavity is the thin fluid-filled space between the two pulmonary pleurae (known as visceral and parietal) of each lung. A pleura is a serous membrane which folds back onto itself to form a two-layered membranouspleural sac. The outer pleura (parietal pleura) is attached to the chest wall, but is separated from it by the endothoracic fascia. The inner pleura (visceral pleura) covers the lungs and adjoining structures, including blood vessels, bronchi and nerves. The pleural cavity can be viewed as a potential space because the two pleurae adhere to each other (through the thin film of serous liquid) under all normal conditions.
