3 years ago

How would i solve 8x squared plus 4x =0

2 answers:

7 0

(8x^2)+4x=0
you would use quadratic formula which is -b +/- square root ((b^2)-4ac)/2a
a: 8
b: 4
c: 0
-4 +/- square root ((4^2)-4(8)(0))/2(8)
(-4+ square root 16)/16 = 0
(-4- square root 16)/16 = -0.5
the two solutions are 0 and -0.5

MAVERICK [17]3 years ago

6 0

8x squared plus 4x =0

A:8
B:4
C:0

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Which polynomial lists the powers in descending order? A. –10 + 4x3 – 4x5 + 2x4 + x7 B. x7 – 4x5 + 2x4 + 4x3 – 10 C. x7 + 4x3 +

Artist 52 [7]

The answer for the exercise shown above is the option B, which is: $x^{7} -4 x^{5} +2 x^{4} +4 x^{3}- 10$
The explanation is shown below:
To list the powers of the polynomial given in the problem above in descending order, you must write the terms from the highest degree to the lowest degree. You have that the highest degree is $7
$ and the lowest degree is $0
$ (Because $-10 x^{0} =-10(1)=-10$ . Therefore, you have that the correct option is the option B.