Simplified answer is: 7xy+4tx
The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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Let the total seed packets needed Anthony to have 90 plants be x.
then,
64:32 :: 90:x
2:1 :: 90:x
90 = 2x
x = 45 seed packets.
________________________
64 plants = 32 seed packets.
1 plant =

seed packets.
90 plants =

seed packets.
Anthony need 45 seed packets to have 90 plants.
!! Hope It Helps !!
X=3
g(3)=3+4=7
f(g(3))=f(7)=78
f(g(3))f(g(3))=6084
is this the correct answer?
Answer:
addition +
Step-by-step explanation:
You always do what's in parenthesis first.