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Helen [10]
4 years ago
9

Quanto é um quinto em porcentagem ?

Mathematics
1 answer:
hram777 [196]4 years ago
8 0
<span>El 20 por ciento es una quinta parte. 1. 20% es 1/5 Para encontrar el 20% de un número, divida entre 5 (Sugerencia / ahorro de tiempo: o divida por 10 y doble) 40% = 2/5, 60% = 3/5; 80% = 4/5; 100% = 5/5.</span>
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Factor out<br> the GCF<br> 56x^2? + 16x + 64
ycow [4]
I’m not 100% sure but I think it’s 4 for the gcf
4 0
3 years ago
Jack left his house and drove at 60 km/h for 5 hours to reach Spencer's house.
Aleks04 [339]

Answer:

6hrs

Step-by-step explanation:

60km x 5 = 300km distance

50km x 6 = 300km distance

7 0
4 years ago
Can someone find x (the height) for me please!!
erica [24]

Answer:

  x = √5

Step-by-step explanation:

The Pythagorean theorem tells you the square of the diagonal is the sum of the squares of the two sides:

  (√7)² = (√2)² + x²

  7 = 2 + x² . . . . . . simplify

  5 = x² . . . . . . . . . subtract 2

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6 0
4 years ago
There is a bag filled with 5 blue and 4 red marbles.
babunello [35]

Answer:  40/81

===========================================

Work Shown:

B = selecting 1 blue

R = selecting 1 red

P(B) = 5/9, since there are 5 blue out of 5+4 = 9 total

P(R) = 4/9, since there are 4 red out of 9 total

P(2 blue) = P(B)*P(B) = (5/9)*(5/9) = 25/81

P(2 red) = P(R)*P(R) = (4/9)*(4/9) = 16/81

The last two equations are valid because we are sampling with replacement. Each selection is independent.

-------------------

P(2 same color) = P(2 blue OR 2 red)

P(2 same color) = P(2 blue) + P(2 red)

P(2 same color) = 25/81 + 16/81

P(2 same color) = (25+16)/81

P(2 same color) = 41/81

-------------------

P(2 different color) = 1 - P(2 same color)

P(2 different color) = 1 - 41/81

P(2 different color) = 81/81 - 41/81

P(2 different color) = (81-41)/81

P(2 different color) = 40/81

4 0
3 years ago
The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0
3 years ago
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