We need to find mean of given integers.
We have -16,39,-10,-16,12,31.
In order to find mean, we need to add all the given inetgers.
Therefore, putting plus sign in between integers.
-16+ 39+ (-10)+(-16)+12+31 .
We will add all positive number 39+12+31 = 82
We will add all negative numbers by negative numbers, -16-10-16 = -42.
Therefore, -16+ 39+ (-10)+(-16)+12+31 = 82 - 42 = 40.
We have given total 6 integers.
So, in order to find the mean, we need to apply following formula
Mean = 
We get,
Mean = 40/6 = 6.66666......
We can round it to 6.67.
Therefore, mean of the given integers = 6.67 (approximately) .
The answers are
11. c) 7x² +5x +8 remainder 7.
12. d) 6x² -6x +3 remainder 2x.
Step-by-step explanation:
Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.
Step 2; By dividing 6
+0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6
+6x³. We subtract this from 6
+0x³ and get -6x³. Now we add this with the -3x² in 6
+0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.
Answer:
it is a
Step-by-step explanation: it took that already
Answer:
im not completely sure but i think its 56.55
sorry if its wrong:/
Step-by-step explanation:
Answer:
The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.
The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm
The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.