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zhannawk [14.2K]
2 years ago
6

Which of the following items is not considered a personal risk factor for ergonomic hazards? A. Body size B. Medical condition C

. Physical condition D. Work environment
Computers and Technology
2 answers:
serious [3.7K]2 years ago
6 0
I think it might be a. body size .
victus00 [196]2 years ago
4 0

Answer:

The correct option to the following question is D.) Work environment.

Explanation:

An Ergonomic hazard is the physical conditions which may be posed to the risk of an injury to a musculoskeletal system such as, the muscles or the ligaments of lower back, nerves or tendons of the hands or wrists, or the bones surrounding near knees, resulting in the musculoskeletal disorder.

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<em>Dinner plate is a type of plate used for main courses. The average dinner plate measures 11 or 12 inches across. This plate is the most used plate during the entire meal and it usually comes out after the salad, it is the plate resting just above the charger.</em>

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What electronic device can represent a KiloByte?
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Military specifications often call for electronic devices to be able to withstand accelerations of 10 g. to make sure that their products meet this specification, manufacturers test them using a shaking table that can vibrate a device at various specified frequencies and amplitudes. if a device is given a vibration of amplitude 9.4 cm, what should be its frequency in order to test for compliance with the 10 g military specification? the acceleration of gravity is 9.81 m/s 2 .

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3 years ago
Life Decisions Cyber Cafe is a cafe with free Internet service and computers that are linked to various online career opportunit
djverab [1.8K]

Answer:

The correct answer is d) all of the above

Explanation:

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3 years ago
Subscribe too my you tube channel for a brainiest
dimaraw [331]

Answer:

Ok

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4 0
2 years ago
Write a Java program in jGRASP that creates a 2D integer array of 5 rows and 20 columns, fills it with increasing integer values
Alex73 [517]

Answer:

As per the question we need to make 5 rowa and 2o columns, in this we have total element 100 so range should be 0 to 99, but we are suggested to keep range 0 to 59, so i have kept the elementns in the range, but if it was a typo in the question for range you do not need to reset the k with zero.

Explanation:

//create a new class  TestArray

public class TestArray {

//define main method

public static void main(String[] args) {

 //declare a 2D array of given size i.e. 5 rows and 20 columns

 int arr[][] = new int[5][20];

 //declare an integer variable k and initialize it with zero, this will used to initialize the array from 0 to 99

 int k = 0;

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //initialize arr with the current value of k

   arr[i][j] = k;

   //once k is 59 set it zero again as we are not going beyond 59

   if(k == 59)

    k = 0;

   //increment value of k with 1

   k++;

  }

 }

 //print the element from the array one by one

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //print the current element of array and an space with it

   System.out.print(arr[i][j]+" ");

  }

  // move the cursor to new line

  System.out.println();

 }

}

}

7 0
3 years ago
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