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WARRIOR [948]
3 years ago
8

Calculate the total cost of an item bought at a negotiated price of $15,640 and a $2,500 trade-in-allowance. The sales tax is 7.

2 percent with an $106 registration fee.
$13,160
$14,372.08
$1,232.08
$14,286.08
Mathematics
1 answer:
Fofino [41]3 years ago
5 0
Hey! :)

The total cost of the item is the second choice which is $14,372.08. I arrived to the answer by simply: 
1) multiplying the sales tax to the negotiated price (15640*.072 = 1126.08) 
2) adding the sales tax to the negotiated price and the registration as well (15640+1126.08+106= 16872.08)
3) subtracting the trade in allowance from the computed value (16872.08 - 2500 = 14372.08)
Hope this helps! :)
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Answer:

a) Sample size = 822

b) Margin of error = 0.03407          

Step-by-step explanation:

We are given the following in the question:

p = 74% = 0.74

a) Sample size is required to obtain margin of error of 0.03

Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

0.03 = 1.96\times \sqrt{\dfrac{0.74(1-0.74)}{n}}\\\\n = (\dfrac{1.96}{0.03})^2(0.74)(1-0.74)\\\\n = 821.24 \approx 822

Thus, the sample size must be approximately 822  to obtain a 95% confidence interval with an approximate margin of error of 0.03

b) Margin of error for the 95% confidence interval

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Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

\text{Margin of error} = 1.96\times \sqrt{\dfrac{0.54(1-0.54)}{822}}\\\\=0.03407

The margin of error now will be 0.03407.

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