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bulgar [2K]
3 years ago
5

A ball on a string moves around a complete circle, once a second, on a frictionless, horizontal table. The tension in the string

is measured to be 6.0N . What would the tension be if the ball went around in only half a second?
Mathematics
1 answer:
ki77a [65]3 years ago
5 0
The tension in the string balances out, and thus equals the centripetal force of the ball 

T = mv^2/r 
<span>
if it only takes half the time to finish one orbit it has to be moving at twice the original speed. </span>
<span>
And since v is squared T will increase by 4 </span>
<span>
T' = m(2v)^2/r </span>
<span>
T' = 4mv^/r = 4T </span>
<span>
T' = 24.0 N

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
</span>
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Natali5045456 [20]

Answer:

A and B

Step-by-step explanation:

- 3/5 is less than -1/5 because it is farther away from 0 on a number line (also, when it comes to figure out which inequality is true with negative number, the smaller one is going to be greater because it is closer to 0 on a number line)

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3 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

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Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

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3 years ago
Jasmine knows that the area of a rectangle is the product of its base and height. Help her write an expression that represents t
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Answer:

Area of rectangle = H × B

Area of rectangle = 10(H)

Step-by-step explanation:

Given:

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Height = H

Find:

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Computation:

Area of rectangle = Height × Base

Area of rectangle = H × B

So,

Area of rectangle = H × B              [Base (B) = 10]

⇒ Area of rectangle = H × 10

⇒ Area of rectangle = 10(H)

6 0
3 years ago
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