A ball on a string moves around a complete circle, once a second, on a frictionless, horizontal table. The tension in the string

Question

bulgar [2K]

3 years ago

5

A ball on a string moves around a complete circle, once a second, on a frictionless, horizontal table. The tension in the string

is measured to be 6.0N . What would the tension be if the ball went around in only half a second?

Mathematics

1 answer:

ki77a [65] · Answer 1 · 2022-02-01T02:45:17+03:00

The tension in the string balances out, and thus equals the centripetal force of the ball

T = mv^2/r

if it only takes half the time to finish one orbit it has to be moving at twice the original speed. 

And since v is squared T will increase by 4 

T' = m(2v)^2/r 

T' = 4mv^/r = 4T 

T' = 24.0 N

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!