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2 years ago

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You are putting a rectangular hot tub on your back porch. It is 6 feet long, 5 feet wide, and 3 feet deep. How much will it cost

to fill the hot tub if water costs $5 per 1000 gallons?

1 answer:

igor_vitrenko [27]2 years ago

5 0

Answer:

$Cost=\$3.66234\approx \$3.67$

Step-by-step explanation:

$Height\ of\ tub=3\ feet\\\\Length\ of\ tub=6\ feet\\\\width\ of\ tub=5\ feet\\\\Volume=Length\times Width\times Height\\\\Volume=6\times 5\times 3=90\ feet^3$

$1\ feet^3=7.48052\ gallons\\\\90\ feet^3=90\times 7.48052=673.2468\ gallons$

$cost\ of\ 1000\ gallons=\$5\\\\cost\ of\ 1\ gallons=\$ \frac{5}{1000}\\\\cost\ of\ 673.2468\ gallons=\$ \frac{5}{1000}\times 673.2468=\$3.366234$

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34 eggs are expected to be used tomorrow

30% of 48 = 14

48-14=34

Step-by-step explanation:

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3 years ago

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The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

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Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

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Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

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- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

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3 years ago

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Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide

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The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

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Given that the hot chocolate is made of 480 grams of milk and 20 grams of cacao.

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<u>The percentage of cacao:</u>

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