Question

Pls I need help this

Answer 1

Answer:

the third side is 4.

Step-by-step explanation:

Using  Pythagorean theorem of a^2 + b^2 = c^2 for right triangles, substitute

the numbers to show ($\sqrt{65})^{2}$ + $b^{2}$ = $9^{2}$ and solve for b. The square root and square cancel each other out, so you get 65 + $b^{2}$ = 81.

Subtract 65 from both sides to get $b^{2}$ = 16.

Then take the square root of both sides to get b = $\sqrt{16}$ which equals 4.