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Viktor [21]
4 years ago
12

If a polygon POLYG is oriented clockwise, what is the orientation of a reflection image P’O’L’Y’G’?

Mathematics
1 answer:
const2013 [10]4 years ago
7 0
The question is not clear.
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(6CQ) Evaluate the limit, or state that the limit does not exist. 2n+7n/13n
Fed [463]

Answer:

option(b)

9/13

Step-by-step explanation:

Given the expression

\frac{2n+7n}{13n}

=\frac{9n}{13n}

n will cancel out on both sides

so,

9/13 will remain

As 9/13 is a constant so any value of n when approaches to a constant will not affect it. Hence limit = 9/13

<h3>It is one of the limit laws that</h3>

The limit of a constant function is equal to the constant.

3 0
4 years ago
Read 2 more answers
Find the value of x in the triangle shown below.<br> 13<br> 5<br> X
LekaFEV [45]

Answer:

A. x = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use PT to solve for the missing side.

<u>Step 2: Identify Conversions</u>

Leg <em>a</em> = <em>x</em>

Leg <em>b</em> = 5

Hypotenuse <em>c</em> = 13

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Substitute:                    x² + 5² = 13²
  2. Isolate <em>x</em> term:              x² = 13²- 5²
  3. Exponents:                   x² = 169 - 25
  4. Subtract:                       x² = 144
  5. Isolate <em>x</em>:                       x = 12
4 0
3 years ago
Is 0.88 greater than 0.875?
sergij07 [2.7K]

Answer:

yeah it has greater value

7 0
3 years ago
Read 2 more answers
In a Gallup poll, 26.6% of 5000 people reported a Body Mass Index (BMI) greater than 30, which is classified as obese. The 5000
PSYCHO15rus [73]

Answer:

The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 5000, \pi = 0.266

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.266 - 2.575\sqrt{\frac{0.266*0.734}{5000}} = 0.25

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.266 + 2.575\sqrt{\frac{0.266*0.734}{5000}} = 0.282

The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)

6 0
3 years ago
I don’t know how to find the equation for this problem
Elis [28]
Try y=3/2x + 3/2

rise over run is 12/8 which simplifies to 3/2

and the y intercept is 1.5 or 3/2
6 0
3 years ago
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