(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
2x^2+4x+34=81
2x^2+4x-47=0
From here just use quadratic formula
Answer: x = 0 y = –3
Step-by-step explanation:
We can solve this system by substitution.
use the second equation as a value for x.
Then substitute that value in place of x in the first equation and solve for y.
6x - 5y = 15 becomes
6(y + 3) - 5y = 15 Distribute 6 × parentheses
6y + 18 - 5y = 15 combine like terms
6y -5y + 18 = 15
y + 18 = 15 Subtract 18 from both sides.
y =15 -18
y = –3
Use this value for y in either equation to solve for x
6x - 5(-3) = 15
6x + 15 = 15 Subtract 15 from both sides, divide by 6 (seems silly!)
x = 0
OR in he second equation,
x = -3 + 3
Again, x = 0
Answer:
It will give you two complex solutions.
An angle - k, its supplement angle is 3k.
Because these angles are supplement , we can write
k+3k=180
4k=180
k=180/4
k=45
Answer:
(っ◔◡◔)っ ♥ the answer is C ♥
Step-by-step explanation:
