4_ compared to 0.45 9

Mathematics

1 answer:

malfutka [58]2 years ago

8 0

Answer:

Step-by-step explanation:

$\dfrac{4}{9}=0.\overline{4}$

The tenths-place digits of the two numbers are the same, 4. So comparison proceeds to the hundredths place. The digit in the hundredths place of 0.4444... is 4, which is less than the digit in the hundredths place of 0.45, which is 5. Hence 4/9 < 0.45.

You might be interested in

The chicken pen held 7 chickens. Each chicken lay 6 eggs a day. How many eggs world they get altogether after 30 days.

Tcecarenko [31]

Answer:

1260 eggs in 30 days

7*6=42

42*30=1260

3 0

1 year ago

Read 2 more answers

ABC is an eqilateral triangle with sides 10cm find the length of the prependicular from A to BC<br>

il63 [147K]

All sides are equal in an equilateral triangle and the perpendicular bisects the side too.

so BC will be bisected and the segments be 5 each.

you can use Pythagoras theorem to find the altitude length, hypotenuse will be one side of the triangle.

$5^2+h^2=10^2$

$h^2=100-25=75$

$h=\sqrt{75}=5\sqrt3$

7 0

3 years ago

In a college student poll, it is of interest to estimate the proportion p of students in favor of changing from a quarter-system

Contact [7]

Answer:

n=206

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.09$ , we can use as prior estimate of p 0.5, since we don't have any other info provided, and we are interested in order to find the value of n, if we solve n from equation (a) we got: