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3 years ago

The answer it’s from acellus

Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

Answer:

quotient-----4

Remainder---1

Step-by-step explanation:

This is basic division am I right?

Opposite of division is Multiplication

Multiplication is repeated addition

4+4+4+4=16

16+4=20 but that is greater than 17.

so quotient is 4 and remainder is 1

jok3333 [9.3K]3 years ago

3 0

Answer and Step-by-step explanation:

4 goes into 17 four times.

4x4= 16

giving you

16 R1

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If x and x+ 10 are a pair of adjacent angle find them

ikadub [295]

Answer:

85° and 95°

Step-by-step explanation:

Given that , x and x + 10 are a pair of angles .

If they will be pair of angles on the same line , then their sum will be 180° .

=> x + x + 10° = 180°

=> 2x = 180° -10°

=> 2x = 170°

=> x = 170°/2

=> x = 85° .

<h3>Hence the two angles are 85° and 95° .</h3>

5 0

3 years ago

Solve and show how you did 5 (x-1) + 3 = 13

Goryan [66]

5(x-1) + 3 = 13
5x - 5 + 3 = 13
5x -2 = 13
5x = 15
x = 15/5
x = 3

4 0

3 years ago

Read 2 more answers

Write down in terms of N and expression for the nth term of the following sequence 25 20 15 10 5

GREYUIT [131]

Answer:

30x-5

Step-by-step explanation:

25-5=20

20-5=15

-5 -10 -15 -20 -25

25 20 15 10 5

I hope that helped you

8 0

3 years ago

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

7 0

2 years ago

57 plus what equals 100

netineya [11]

Answer: 43

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers