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ANTONII [103]
4 years ago
9

The difference between Alan's and Bea's age is three years. The sum of their ages is twenty-seven years. How old are they if-

Mathematics
2 answers:
Anna [14]4 years ago
5 0
Alright. Take x as Alan's age, and y as Bea's age. We can start writing equations; from the first sentence, we find that x - y = 3. From the second sentence, x + y = 27. Adding the two equations, gives 2x = 30. Thus, x is 15, and it follows, that y = 15 - 3, or 12. So for A, Alan is 15, and Bea is 12, and for B, Bea is 15, and Alan is 12.
11Alexandr11 [23.1K]4 years ago
4 0
A - b = 3
a + b = 27
--------------add
2a = 30
a = 30/2
a = 15 <=== alan is 15

a + b = 27
15  + b = 27
b = 27 - 15
b = 12 <=== bea is 12 
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7 0
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What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

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