Answer:
Step-by-step explanation:
You have to move the variables (r and t) with u to isolate s.
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Answer:
Step-by-step explanation:
x²+y²-2x-10y+1=0
compare with x²+y²+2gx+2fy+c=0
center is (-g,-f)
radius=√(g²+f²-c)
2g=-2
g=-1
2f=-10
f=-5
radius=(1,5)
c=1
let eq. of circle be x²+y²-2x-10y+c=0
∵ it passes through (2,-3)
2²+(-3)²-2(2)-10(-3)+c=0
4+9-4+30+c=0
c=-39
eq. of circle is is x²+y²-2x-10y-39=0
Answer:
A, the graph is shown
Step-by-step explanation:
Answer:
No
Because you can't find any of the length if you don't have two other lengths
Step-by-step explanation:
study cosine rule and sine rule
you use cosine rule when you have one angle in-between two length
while you use sine rule when you have two angles and one length
just study cosine rule and sine rule you will understand what am saying
<span> we have that
standard form of equation for parabola:
(x-h)^2=-4p(y-k)
(h,k) --------->being the (x,y) coordinates of the vertex.
Parabola opens downwards because focus is below vertex on the axis of symmetry.
For given problem:
</span><span>vertex: (-3,2)
axis of symmetry: x=-3
p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
4p=12
Directrix: y=2+p=5
Equation:
(x+3)^2=-12(y-2)
the answer is </span>(x+3)^2=-12(y-2)
