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2 years ago

13

Describe two ways you can show that 1 is congruent to 7

1 answer:

marysya [2.9K]2 years ago

6 0

Two ways to show that 1 is congruent to 7 is 1+6=7 and 10-3=7

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62.52=27.39+t this is 7th grade math! plsss help!!1

Tju [1.3M]

Answer:

Hope it helps you friend

and please mark me as

BRAINLIEST

6 0

2 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

2 years ago

Read 2 more answers

Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then

Scrat [10]

Given the function :

$f(x)=\sqrt[]{x+2}+1$

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)

$x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1$

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)

$\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\ \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\ \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\ \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}$

the graph of the function and the points will be as shown in the following image :

5 0

10 months ago

three different accounts are described below. order the accounts to their values after 10 years, from greatest to least.

Sedbober [7]

Answer

You deposit $800 in an account that earns 7.5% annual interest compounded quarterly.

Step-by-step explanation:

From the close eye, this seems to me the best and most factual answer to be found!! Goodluck with your quiz!

6 0

2 years ago

Read 2 more answers

How to solve Y = eight, X =2 and direct variation

rodikova [14]

Answer:

The answer is k = 4.

Step-by-step explanation:

Given:

Y = 8 and X = 2.

Now, to solve direct variation.

$y$ direct with $x$ .

Now, using equation to solve direct variation:

$y=kx$

$8=k\times 2$

Dividing both sides by 2 we get:

$4=k$ .

Therefore, the answer is k = 4.

5 0

3 years ago