Subtract 153-63=90 and I am pretty sure that's what you have to do
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
Answer:
real:√2, 3,-1, 1/2 etc
natural: 1,2,3,4,5,6.....(0 is not included)
integers:. .............-4,-3,-2,-1,0,1,2,3,4........ etc
rational: nos. which are in p/q form
:1/2,3/4,4/9 etc
irrational: nos. which cannot be written in p/q form
: √2,√3... etc
irrational: √2, √3, √5, √11, √21, π(Pi)
Answer:
34 rolls
Step-by-step explanation:
For Frank to cover his whole ceiling, he needs paper that will cover
20 ft x 20 ft
20 x 20 = 400 ft
So, Frank needs to cover 400 ft of the ceiling. He has to split up this large need for paper into smaller rolls, because the rolls he can buy are small.
If each roll has 12 ft, we need to find how many 12-feet are in 400 feet.
To do this, we should divide
400 / 12
= 33.333
Because Frank cannot cover the whole ceiling using only 33 rolls, he has to buy an additional roll to make sure he can cover the extra area [that would be left over if he were to only buy 33 rolls, which would only cover 396 feet]
So, Frank will need to buy 34 rolls to have enough paper to entirely cover his ceiling.
