3(x-1)-8=4(1+x)+5
One solution was found :
x = -20
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(x-1)-8-(4*(1+x)+5)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((3•(x-1))-8)-(4•(x+1)+5) = 0
Step 2 :
Equation at the end of step 2 :
(3 • (x - 1) - 8) - (4x + 9) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-x - 20 = -1 • (x + 20)
Equation at the end of step 4 :
-x - 20 = 0
Step 5 :
Solving a Single Variable Equation :
5.1 Solve : -x-20 = 0
Add 20 to both sides of the equation :
-x = 20
Multiply both sides of the equation by (-1) : x = -20
One solution was found :
x = -20
hope this is wht u wanted
Answer:
<em><u>a,e and b</u></em>
Step-by-step explanation:
Answer: C. X + 44
Step-by-step explanation:
Let x be the unknown number.
Given statement : "44 more than an unknown number".
By using addition operation ,
Mathematical expression for "44 more than an unknown number" = 44 +x
Hence, the correct expression is x+44.
So, the correct option is C.
Answer:
0.75
Step-by-step explanation:
Given,
P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,
P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,
Where,
A = event that the selected student has a Visa card,
B = event that the selected student has a MasterCard,
C = event that the selected student has an American Express card,
We know that,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07
= 0.75
Hence, the probability that the selected student has at least one of the three types of cards is 0.75.
Just add up all the angles hope you get it right
