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3 years ago

MARKING BRAINLIEST HELP

Mathematics

2 answers:

Alenkinab [10]3 years ago

7 0

Answer:

Step-by-step explanation:

Juliette [100K]3 years ago

3 0

I believe c! Good luck

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John decided to look at new and used cars. John found a used car for $6000. A new car is $18000, so what percent of the price of

vladimir2022 [97]

John decided to look at new and used cars. John found a used car for $6000. A new car is $18000, so what percent of the price of a new car does John pay for a used car? Round your answer to the nearest tenth if necessary.

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3 years ago

Read 2 more answers

Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.

statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that $p = \frac{231}{361} = 0.6399$

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095$

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

$E = -31*0.4095 + 21*0.5905 = -0.29$

The expected value of the proposition is of -0.29.

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2 years ago

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I did it wrong the first time you're answer is b. 11*11^4

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3 years ago

Is the line through points P(2,-9) and Q(6, -13) perpendicular to the line through points R(5,-1) and

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