Let B be between A and C. If AB = 3x + 5, BC = 5x - 1, AC = 36, solve for x.

Mathematics

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

The value of x is 4.

Step-by-step explanation:

Given:

Let B be between A and C.

$AB = 3x + 5$

$BC = 5x - 1$

$AC = 36$

To Find:

x=?

Solution:

B be between A and C as shown in Figure

A-B-C such that

$AC=AB+BC$ ...........Line Addition Property

Substituting the given values we get

$36=3x+5+5x-1=8x+4\\\\\therefore 8x=36-4=32\\\\\therefore x=\dfrac{32}{8}=4\\\\\therefore x=4$

The value of x is 4.

You might be interested in

A portion of a hiking trail slopes upward at about a 6 angle. To the nearest tenth of a foot, what is the value of x, the distan

kirza4 [7]

The distance covered by the hiker if he traveled a horizontal distance of 120 ft at and angle of 6° will be given by:
cos θ=adjacent/hypotenuse
let the hypotenuse be h, adjacent =120 ft, θ=6°, thus plugging in the values we shall have:
cos 6=120/h
h=120/cos 6
h=120.661 ft
Answer: 120.661 ft

5 0

3 years ago

-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)

Korolek [52]

$-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}$

=========================================================

$8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}$

=========================================================

$10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}$

6 0

2 years ago

Read 2 more answers

Question 28 of

Helen [10]

$y - y1 = m(x - x1) \\ y - 8 = 15(x - 2) \\ y - 8 = 15x - 30 \\ y = 15x - 30 + 8 \\ y = 15x - 22$