Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 41. g of hexane is mi
xed with 150. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.
The balanced chemical equation for the reaction of hexane with O₂ is given below; 2C₆H₁₄ + 19O₂ --> 12CO₂ + 14H₂O Stoichiometry of hexane to oxygen is 2:19 number of hexane moles - 41 g / 86.2 g/mol = 0.476 mol number of oxygen moles - 150 g / 32 g/mol = 4.69 mol we need to find which reagent is the limiting reactant If hexane is the limiting reactant 2 moles of hexane reacts with -19 mol of oxygen therefore 0.476 mol - 19/2 x 0.476 = 4.522 mol since 4.69 mol of oxygen is present, O₂ is in excess and hexane is the limiting reactant. stoichiometry of hexane to water is 2:14 2 mol of hexane gives 14 mol of water therefore 0.476 mol of hexane forms - 14/2 x 0.476 - 3.33 mol mass of water formed - 3.33 mol x 18.0 g/mol = 59.9 g
Two of the strongest forms of chemical bond are the ionic and the covalent bonds. Chemical bonds form between two atoms, each with its own electron environment
