A reaction of heating potassium permanganate produces

If 3.68 grams of zinc were allowed to react with excess hydrochloric acid to produce zinc chloride and hydrogen gas, how much zi

AysviL [449]

Answer:

Here... Since there is excess HCl, you know the Zinc will be the limiting reagent. I was able to create the reaction equation based on the info you gave: Z + 2HCl ----> ZCl2 +2H. Now, in order to find the theoretical yield of ZCl, you need to convert Zinc from grams to moles. Do this by dividing by its molar mass (65.38), thus: 3.68 (g) / 65.38 (g/mol) = 0.056286... moles.

Now, using the balanced equation we made earlier, we see that 1 mole of Zinc creates 1 mole of ZCl2. Thus our ratio is 1:1. This makes the next step easy. Since it is 1:1, we multiply the number of moles we have of Zinc (0.056286...) by the number of moles it will create of ZCl (1). (0.056286)(1) = 0.056286 moles ZCl. Now convert this to grams by multiplying by its molar mass (136.28) and you get 7.67 grams. This is your theoretical yield. The percent yield is found by dividing the actual amount obtained (7.12 g.) by the theoretical yield (7.67 g.) then multiply that by 100%. When this is done, your Percent Yield is about 92.8%

6 0

3 years ago

!!!! If you need more information just let me know.

e-lub [12.9K]

What basically your question is can you tell

8 0

3 years ago

Consider the formation of nitryl fluoride: 2NO2(g)+F2(g)⇌2NO2F(g) The reaction is first order in F2 and second order overall. Wh

Dahasolnce [82]

Answer:

Rate = $k[NO_{2}][F_{2}]$

Explanation:

Two reactants are present in this reaction which are $NO_{2}and F_{2}$
We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.
Here, overall order of reaction is 2 including first order with respect to $F_{2}$
So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to $NO_{2}$
So, rate law: rate = $k[NO_{2}][F_{2}]$

7 0

3 years ago

The first-order reaction, so2cl2 → so2 + cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 k. what percentage of the init

Svetradugi [14.3K]

For the 1st order reactions,rate constant (k) is mathematically expressed as

k = $\frac{2.303}{t}log \frac{Co}{Ct}$
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = $\frac{2.303}{7200}log \frac{100}{Ct}$
∴ $log\frac{100}{Ct}$ = 0.06877
∴, $\frac{100}{Ct}$ = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>

4 0

3 years ago

Extra points & brainlest to anyone that can help me with both answers

ki77a [65]

Answer:

1st blank: Organelles

2nd blank: Plant

3rd blank: chloroplasts

3 0

3 years ago