Answer:
0.013 mole.
Explanation:
From the question given above, the following data were obtained:
Time (t) = 94.6 mins
Current (I) = 224.8 mA.
Mole of electrons (e) =?
Next, we shall convert 94.6 mins to seconds. This is illustrated below:
1 min = 60 s
Therefore,
94.6 mins = 94.6 min × 60 s / 1 min
94.6 mins = 5676 s
Thus, 94.6 mins is equivalent to 5676 s.
Next, we shall convert 224.8 mA to ampere (A). This can be obtained as follow:
1 mA = 1×10¯³ A
Therefore,
224.8 mA = 224.8 mA × 1×10¯³ A / 1 mA
224.8 mA = 0.2248 A
Thus, 224.8 mA is equivalent to 0.2248 A.
Next, we shall determine the quantity of electricity flowing in circuit. This can be obtained as follow:
Time (t) = 5676 s
Current (I) = 0.2248 A
Quantity of electricity (Q) =?
Q = it
Q = 0.2248 × 5676
Q = 1275.96 C
Finally, we shall determine the mole of electron by converting the quantity of electricity (i.e 1275.96 C) to number of electrons. This can be obtained as follow:
96500 C = 1 e
Therefore,
1275.96 C = 1275.96 C × 1 e / 96500 C
96500 C = 0.013 e
Thus, the mole of electron trasfered in the process is 0.013 mole.
