How many oxygen atoms are contained in the following chemical formula? 2agno3

How many significant figures are in 136,000 ml?

WINSTONCH [101]

Answer:

There are 3 sig figs

Explanation:

Sig figs are the amount of figures counting from the left side of the number until you reach the first zero. Starting from the left, I counted one, three, and six. That's 3 numbers, and therefore, that's how we got our answer. The only exception is when there is a decimal. Then all the numbers before the decimal, despite whether or not they're zeros, are sig figs.

8 0

3 years ago

Read 2 more answers

In the laboratory, a student dilutes 13.5 mL of a 11.6 M hydroiodic acid solution to a total volume of 100.0 mL. What is the con

igomit [66]

Answer: The concentration of the diluted solution is 1.566M.

Explanation:

The dilution equation is presented as this: $M_{s} V_{s} =M_{d} V_{d}$ .

·M= molarity (labeled as M)

·V= volume (labeled as L)

·s= stock solution (what you started with)

·d= diluted solution (what you have after)

Now that we know what each part of the formula symbolizes, we can plug in our data.

$11.6M*13.5mL=M_{d} *100mL$

We cannot leave it like this because the volumes must be in Liters, not milliliters. To convert this, we divide the milliliters by 1000.

$13.5mL/1000=0.0135L$ $100mL/1000=0.1L$

Now that we have the conversions, let's plug them into the equation.

$11.6M*0.0135L=M_{d} *0.1L$

The only thing that we need to do now is actually solving the answer.

$M_{d} =\frac{11.6M*0.0135L}{0.1L}$ $M_{d} =1.566M$

From the work shown above, the answer is 1.566M.

I hope this helps!! Pls mark brainliest :)

7 0

2 years ago

Explain why vanadium (radius=134 pm) and copper (radius=128 pm) have nearly identical atomic radii, even though the atomic numbe

Viktor [21]

<span>There are few main factors affecting the atomic radii, the outermost electrons and the protons in the nucleus and also the shielding of the internal electrons. I would speculate that the difference in radii is given by the electron clouds since the electrons difference in these two elements is in the d orbital and both has at least 1 electron in the 4s (this 4s electron is the outermost electron in all the transition metals of this period). The atomic radio will be mostly dependent of these 4s electrons than in the d electrons. Besides that, you can see that increasing the atomic number will increase the number of protons in the nucleus decreasing the ratio of the atoms along a period. The Cu is an exception and will accommodate one of the 4s electrons in the p orbital.

</span><span>Regarding the density you can find the density of Cu = 8.96g/cm3 and vanadium = 6.0g/cm3. This also correlates with the idea that if these two atoms have similar volume and one has more mass (more protons; density is the relationship between m/V), then a bigger mass for a similar volume will result in a bigger density.</span>

7 0

3 years ago

Which two particles in an atom are equal in mass

Taya2010 [7]

Protons and neutrons.

Note: They probably are ABOUT the same mass. Don't think they are exactly the same.

Hope this helps!

8 0

3 years ago

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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r

denis23 [38]

Answer :

(1) The frequency of photon is, $3\times 10^{10}Hz$