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yawa3891 [41]
3 years ago
13

How many oxygen atoms are contained in the following chemical formula? 2agno3

Chemistry
1 answer:
sesenic [268]3 years ago
7 0

It would be: 2*3 = 6 oxygen atoms

OPTION D IS YOUR ANSWER......

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If you are given an ideal gas with pressure (p)259,392.00 pa and temperature (T)=200°c of 1 mole Argon gas in a volume 8.8dm3,ca
GuDViN [60]

Answer: R=4.82436 \frac{Pa. m^{3}}{mol. K}

Explanation:

The Ideal Gas equation is:  

P.V=n.R.T  (1)

Where:  

P is the pressure of the gas  

n the number of moles of gas  

R=8.3144598 \frac{Pa. m^{3}}{mol. K} is the gas constant  

T is the absolute temperature of the gas in Kelvin.

V is the volume

It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be 8.3144598 \frac{Pa. m^{3}}{mol. K}.

However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.

Having this clarified, let's isolate R from (1):

R=\frac{PV}{nT}  (2)

Where:

P=259392 Pa

n=1 mole

T=200\°C=473.15 K is the absolute temperature of the gas in Kelvin.

V=8.8 dm^{3}=0.0088 m^{3}

R=\frac{(259392 Pa)(0.0088 m^{3})}{(1 mole)(473.15 K)}  (3)

Finally:

R=4.82436 \frac{Pa. m^{3}}{mol. K}  

4 0
3 years ago
230g sample of a compound contains 136.6g carbon, 26.4g hydrogen, and 31.8g nitrogen. What is masspercentif oxygen
natulia [17]

Answer:

15.3 %

Explanation:

Step 1: Given data

  • Mass of the sample (ms): 230 g
  • Mass of carbon (mC); 136.6 g
  • Mass of hydrogen (mH): 26.4 g
  • Mass of nitrogen (mN): 31.8 g

Step 2: Calculate the mass of oxygen (mO)

The mass of the sample is equal to the sum of the masses of all the elements.

ms = mC + mH + mN + mO

mO = ms - mC - mH - mN

mO = 230 g - 136.6 g - 26.4 g - 31.8 g

mO = 35.2 g

Step 3: Calculate the mass percent of oxygen

%O = (mO / ms) × 100% = (35.2 g / 230 g) × 100% = 15.3 %

6 0
3 years ago
Which of the following characteristics do Element I and Element I have in common?
Nesterboy [21]

Answer:

Option C. The same number of energy levels.

Explanation:

From the diagram given above, element (i) belong to group 2 while element (ii) belong to group 6.

Also, both element i and ii belong to the same period (i.e period 4). This simply means that both element i and ii have the same number of energy levels.

NOTE: Elements in the same period have the same number of shells of electrons which simply means they have the same energy levels.

5 0
3 years ago
Determine the energy change in the following reaction. This reaction is considered ...
Juliette [100K]

Answer:isothermic

Explanation:

8 0
3 years ago
Read 2 more answers
Even though the same amount of energy was transferred into both substances from the air, the isopropanol evaporated while the wa
Nesterboy [21]

Answer:

The isopropanol evaporated while the water did not because the molecules don't stick together as strongly as the molecules in the water do. The water would need more energy transferred in, in order to evaporate.

Explanation:

4 0
3 years ago
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