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ExtremeBDS [4]
3 years ago
8

If the empirical formula of a compound is C2OH4, and the molar mass is 88 g/mol, what is the molecular formula

Chemistry
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

               Molecular Formula = C₄O₂H₈

Explanation:

Molecular formula is calculated from following formula.

Molecular Formula = n(Empirical formula)

The formula for n is given as,

n = Molecular Formula Mass / Empirical Formula Mass

Molecular Formula mass = 88 g/mol

Empirical formula mass = 44

Putting values,

n = 88 / 44 = 2

Now,

Molecular Formula = 2(C₂OH₄)

Molecular Formula = C₄O₂H₈

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A gas has a volume of 5.0 L at a pressure of 50 kPa. What happens to the volume when temperature is held constant and the pressu
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At rest, a neuron has a lower concentration of sodium than the surrounding fluid. The neuron also has a higher concentration of
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a. Remaining at rest requires the use of ATP.

Explanation:

The resting membrane potential is maintained by the sodium-potassium pump. The sodium potassium pump does this by actively pumping sodium ions out of the cell and potassium ions inside the cell in a ratio of 3:2. This movement of ions by the sodium-potassium pump is against their concentration gradient. In a neuron at rest, there are more sodium ions outside the cell than there are inside the cell. Also, there are are more potassium ions inside the cell than there are outside the cell. However, there are ion channels through which these ions enter and leave the cell. Sodium ion channels allow sodium to enter the cell following its concentration gradient, whereas, potassium ion channels allow potassium to leave the cell following its concentration gradient. However, more potassium ions leave the cell than do sodium ions enter the cell because of the higher permeability of the cell to potassium ions.

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Why isn't the atomic mass of most of the elements on the Periodic Table an integer (not a decimal)?
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`Silver salts have antimicrobial properties--they can kill bacteria by interfering with certain proteins. Silver nitrate used to
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Explanation:

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The atoms of oxygen in 2.0 moles of silver nitrate are:

2.0molAgNO_{3}.\frac{6.02\times10^{23}moleculeAgNO_{3}  }{1molAgNO_{3}} .\frac{3atomO}{1moleculeAgNO_{3}} =3.6\times10^{24}atomO

3 0
3 years ago
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