1. Use both methods to find the distance between the points on the number line. Method A: Count the number of units between the
points. Method B: Take the absolute value of the difference of the two numbers. When taking the absolute value, show that the greater number or the lesser number can be the subtrahend (the number subtracted).
-12 and 19 on a number line are shown (I cant put in the pic)
-12 and 19 on a number line are shown (I cant put in the pic)
2 answers:
Answer:
The distance between the points is 31.
Step-by-step explanation:
Consider the provided information.
Method A: Count the number of units between the points.
Consider the figure shown and cont the units between the point -12 and 19.
There are 31 units between -12 and 19.
Hence, the required answer is 31.
Method B: Take the absolute value of the difference of the two numbers.
Subtract the number using absolute value.
We can find the difference with two ways:
Way 1: Subtract smaller number(-12) from the bigger number(19).
|19 -(- 12)| = |19+12| = 31
Way 2: Subtract bigger number(19) from the smaller number(-12).
|-12 - 19| = |-31|
Hence, the distance between the points is 31.
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If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
Answer:
A. The larger the sample size the better.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation
In this question:
We have to look at the standard error, which is:
This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.