First find the area of the leftmost rectangle:

A=l*w
A=4*2 (the 2 comes from 5-3)
A=8

Then find the area of the rightmost rectangle:

A=l*w
A=3*3 (the second 3 comes from 4-1)
A=9

So when you add 8 and 9, you get 17

Hope this helps

4 0

3 years ago

Read 2 more answers

8 7/10 - 3 4/10 pls help im so behind

nadezda [96]

Answer:

8 7/10 - 3 4/10 = 5.3, 5 3/10, or 53/10

5.3, 5 3/10, and 53/10 all equals to 8 7/10 - 3 4/10 :)

Step-by-step explanation:

6 0

3 years ago

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The perimeter of a rectangle is twice the sum of its length and it’s width . The perimeter is 22 meters and I it’s length is 2 m

lukranit [14]

Answer:

The length of this rectangle is 8m.

Step-by-step explanation:

The problem states that the perimeter of a rectangle is twice the sum of its length and it’s width. So

$P = 2*l + 2*w$

The problem also states that the perimeter is 22 meters. So:

$P = 22$

$2l + 2w = 22$ .

Also, it states that I is the length and it is 2 meters more then twice it’s width. So

$l = 2w + 2$

What’s its length?

$P = 22$

$2l + 2w = 22$

$2(2w+2) + 2w = 22$

$4w + 4 + 2w = 22$

$6w = 22 - 4$

$6w = 18$

$w = \frac{18}{6}$

$w = 3$

The width is 3m. The length is in function of the width, so:

$l = 2w + 2$

$l = 2*3 + 2$

$l = 8m$

The length of this rectangle is 8m.

4 0

4 years ago