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3 years ago

How many days would it take a construction loan of $548,048 to earn$50,000 exact interest at 9% interest rate?

2 answers:

8 0

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &50000\\
P=\textit{original amount deposited}\to& \$548048\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years
\end{cases}
\\\\\\
50000=548048\cdot 0.09t\implies \cfrac{50000}{0.09(548048)}=t\implies 1.014\approx t$

SOVA2 [1]3 years ago

3 0

Answer:

The answer is 370 days

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What is the midpoint of RS with endpoints R (-8, 3) and S (9, – 7)?

lubasha [3.4K]

Answer:

Midpoint coordinates are $(x,y) = (\frac{1}{2} , -2)$

Step-by-step explanation:

The Coordinates of R = (-8,3)

The Coordinates of S = (9, -7)

Let M be the mid point of M and its coordinates by (x,y)

Now, by mid point formula,

$(x,y) = (\frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2} )$

⇒ $(x,y) = (\frac{1}{2} ,\frac{-4}{2} ) = (\frac{1}{2} , -2)$

So, the midpoint coordinates are $(x,y) = (\frac{1}{2} , -2)$

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3 years ago

help solve this problem Based on a poll, 62% of Internet users are more careful about personal information when using a public

erma4kov [3.2K]

Answer

The probability that among four randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.979.

Step-by-step explanation:

Since 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot.

Therefore, the Probability of 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot is, p=0.62.

We have to find the probability that at least one user is more careful about personal information when using wi-fi hotspot.

Probability of internet users are not more careful about personal information when using a public wi-fi hotspot, i.e $q=1-p$

$q=1-0.62=0.38$

Use Binomial Distribution, i.e, $P\left ( X \right )=^nC_xp^xq^\left ( n-x \right )$

p=0.62, q=0.38, n=4.

Required Probability $P\left ( X\geq 1 \right )=P\left ( X=1 \right )+P\left ( X=2 \right )+P\left ( X=3 \right )+P\left ( X=4 \right )$

$P\left ( X\geq 1 \right )=1-P\left ( X=0 \right )$

=1- $^4C_0p^0q^\left ( 4-0 \right )$

=1- $4\cdot1\cdot q^\left ( 4-0 \right )$

=1- $4\cdot \left ( 0.38 \right )^4$

=1-0.02085136=0.97914864

Therefore, the probability that at least one users more careful about personal information when using wi-fi hotspot, i.e 0.979(approx).

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2 years ago

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Answer:

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Step-by-step explanation:

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1 year ago

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2 years ago

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