m=18 when r = 2.
Step-by-step explanation:
Given,
m∝
So,
m = k×,--------eq 1, here k is the constant.
To find the value of m when r = 2
At first we need to find the value of k
Solution
Now,
Putting the values of m=9 and r = 4 in eq 1 we get,
9 = 
or, k = 36
So, eq 1 can be written as m= 
Now, we put r =2
m = 
or, m= 18
Hence,
m=18 when r = 2.
Answer:
A. d ≤ –7 or d > 8.
Step-by-step explanation:
Given : 2d + 3 ≤ –11 or 3d – 9 > 15.
To find : What are the solutions of the compound inequality .
Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.
For 2d + 3 ≤ –11
On subtracting both sides by 3
2d ≤ –11 - 3 .
2d ≤ –14.
On dividing both sides by 2 .
d ≤ –7.
For 3d – 9 > 15.
On adding both sides by 9.
3d > 15 + 9 .
3d > 24 .
On dividing both sides by 3 .
d > 8 .
So, A. d ≤ –7 or d > 8.
Therefore, A. d ≤ –7 or d > 8.
Answer:
158
Step-by-step explanation:
Simplify the following:
2×5×3 + 2×5×8 + 2×3×8
5×3 = 15:
2×15 + 2×5×8 + 2×3×8
5×8 = 40:
2×15 + 2×40 + 2×3×8
3×8 = 24:
2×15 + 2×40 + 2×24
2×15 = 30:
30 + 2×40 + 2×24
2×40 = 80:
30 + 80 + 2×24
2×24 = 48:
30 + 80 + 48
| 8 | 0
| 4 | 8
+ | 3 | 0
1 | 5 | 8:
Answer: 158
Answer:
C. 2(k +2)(k +5)(k +1)
Step-by-step explanation:
The LCM will be the product of unique factors.
The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:
2(k+1)(k+2)(k+5) . . . . matches choice C
x = x
Consider x. Let x be a quantity denoted in the real numbers equal to x. Now, some properties of the real numbers include closure under the four basic operations.
