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DerKrebs [107]
3 years ago
8

What is the answer plz help

Mathematics
1 answer:
Serhud [2]3 years ago
7 0
The answer is A) candy
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Help please i don’t understand and this is do today :/!!
aleksklad [387]
The answer is 6.4
This is why

8 0
3 years ago
On Babylonian tablet YBC 4652, a problem is given that translates to this equation:
Strike441 [17]
The solution is
x = 52.5
3 0
2 years ago
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How many inches are in a foot then converted into millimeters
Semmy [17]
There are 12 inches in a foot. When you convert 12 into millimeters, it becomes 304.8.
6 0
3 years ago
1) write a system on equations with the solution (2, -3). Work the problem out using the substitution method
solmaris [256]

The system of the equations that have the solution of (2, -3) are given below.

3x + 2y = 0 and 3y = 2x - 13

<h3>What is the linear system?</h3>

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

Write a system of equations with the solution (2, -3).

From a single point, an infinite number of lines pass through this point.

Let one line is passing through the origin. Then the equation of the line will be

\rm y  = \dfrac{-3}{2} (x)\\\\y = -1.5x

And the other line is perpendicular to the line which is passing through the origin and a point (2, -3).

\rm y = \dfrac{2}{3} x + c

Then this line also passes through a point (2, -3). Then the value of c will be

\rm -3 = \dfrac{2}{3} \times 2 + c\\\\c \ \  = -13

Then the equation of the line will be

3y = 2x -13

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ4

8 0
1 year ago
What is the answer to this equation “A = ?”<br><br> G(a + h) = M
sasho [114]

Answer:

a  = M -Gh/G

Step-by-step explanation:

in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.

G(a + h) = M

Ga + Gh  = M

Ga = M - Gh

since G is disturbing a from standing alone, we divide both sides by G

Ga/G = M- Gh/ G

a  = M -Gh/G

7 0
3 years ago
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