The two quantities we want to analyze are

and

We wonder if the first if 12 times the second. Let's compute them both to begin with:

and

So, the question is: is 341682 twelve times 131880? The check is very simple:

So the answer is no
3 : 3,6,9,12,15,18,21,24,27,30
4 : 4,8,12,16,20,24,28,32,36
7: 7,14,21,28,35,42,49,56,63
9: 9,18,27,36,45,54,63,72,81
Answer:
Given the domain, the range for 3x-y = 3 is {-9, 6, 9}
Step-by-step explanation:
First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y
⇒ y = 3x - 3.
Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).
f(-2) = -9
f(2) = 6
f(4) = 9.
Finally, the range for the given domain is {-9, 6, 9}
The volume of a sphere with radius
.
Here the radius is
. The volume is

108+621=729
So then 729-100=629
Therefore your answer is 629