The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.
1 answer:
The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
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Step-by-step explanation:
You should prolly subtract 2 from both sides first.
So you get, -|2/5x + 3| > -1 2/5
- Add three to both sides
- -|2/5x| = -1 2/5
- Do -1 and 2/5 divided by 2/5 to get -3.5, x > -3.5
One of the answers is x > -3.5 but you need to switch the sign to less than and make the other side the opposite.
You see that, switched the sign and made whats on the right side opposite. So now solve for x again but with this new equation. Also, the parentheses are absolute value signs
Subtract 3 from both sides
-|2/5x| < -1 and 3/5
Divide 2/5 from each side to get x < -4
I hope I'm correct, my bad if I'm wrong
