√-1 factor completely without any 'i'

Mathematics

1 answer:

Tanzania [10]3 years ago

8 0

Answer:

the root of -1 is -1

Step-by-step explanation:

When multiplied by itself, the root is typically a specified number of times gives a specified number or quantity. So -1 × -1 = -1

So there you go

You might be interested in

Helppp me plz Srry again

Kay [80]

Step-by-step explanation:

I am really very sorry about this because I can't answer of this question because I can't understand I am sooooo sorry

4 0

3 years ago

Work out the input for this function machine

Delicious77 [7]

Answer:

Answer is 12 isnt it

Step-by-step explanation:

12×4=48

48+9=57

4 0

2 years ago

Cho f(t)=(t-4)u(t-2)phep bien doi laplace la F(s)=e^-2s/s^2-2e^-2s/s62

FinnZ [79.3K]

Step-by-step explanation:

cho f(t)=(t-4)u(t-2)phep bien doi laplace la

F(s)=e^-2s/s^2-2e^-2s/s62

4 0

3 years ago

What is the product of and (6+5i) and (3-7i) ? -17-27i -17+27i 53+27i 53-27i

USPshnik [31]

We are going to make the product step by step.
We have:
(6 + 5i) * (3-7i)
Multiplying:
((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
Rewriting:
18 - 42i + 15i - 35i ^ 2
18 - 42i + 15i - 35 * (- 1)
18 - 42i + 15i + 35
53 - 27i
Answer:
the product of and (6 + 5i) and (3-7i) is:
53-27i

5 0

3 years ago

8x^-9+(-3x^-3y-2)(5/x^6y-2)

DaniilM [7]

$8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})$