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3 years ago

How many neutrons does the following nuclide have? 253/100 Fm A. 253 B. 100 C. 153 D. none of these

Chemistry

2 answers:

TiliK225 [7]3 years ago

5 0

Answer : The correct option is, (C) 153

Explanation :

Atomic number is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and number of neutrons.

Number of neutrons = Mass number - Number of protons

or,

Number of neutrons = Mass number - Atomic number

As we are given that:

The given nuclide is, $^{253}_{100}Fm$

'Fm' is the fermium element.

Mass number of 'Fm' = 253

Atomic number f 'Fm' = 100

Now we have to determine the number of neutrons.

Number of neutrons = Mass number - Atomic number

Number of neutrons = 253 - 100

Number of neutrons = 153

Therefore, the number of neutrons in the 'Fm' nuclide have 153.

lara [203]3 years ago

3 0

I believe the correct answer is C. The number of neutrons in the <span>253/100 Fm would be 153. The numbers beside Fm are used to determine this. Two hundred fifty three represents the mass number which is the sum of protons and neutrons in the nuclide while 100 represents the atomic number which is the number of protons. Therefore,

253 = neutrons + 100
neutrons = 153</span>

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Calculate the number of moles of O2 produced using the ideal gas law. Then, use this value to calculate the number of moles of h

aev [14]

Answer:Given data from the lab collated as 291.15k for Temperature, 0.061L for volume and 1atm pressure.

Initial hydrogen peroxide solution is 5ml with a weigh % concentration 6.6%

n=0.0025moles of oxygen AND 0.0097moles of H2O2 were present

Explanation:

2H2O2(aq)-----2H2O(I)+2O2(g)

Recall the idea gas equation

PV=nRT

n=PV/RT---(1) solving equation (1) using the data in the answer section above.

n=0.0025moles of oxygen is produced.

Recall that for every 100ml of solution you get 6.6g of hydrogen peroxide.

Your 5ml will thus contain

5ml*6.6g H2O2/100ml=0.33g

no of moles if H2O2=0.33/34.015=0.0097moles

6 0

3 years ago

How many grams of NaCl is needed to make 750mL of a 2.4 M NaCl solution?

Aleksandr [31]

Answer:

Molarity of the solution = 3.000 M

Volume of the solution = 250.0 mL = 0.25 L

moles in 250.0 mL = molarity x volume of the solution

= 3.000 M x 0.25 L

= 0.75 mol

Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.

Moles (mol) = mass (g) / molar mass (g/mol)

Moles of NaCl in 250.0 mL = 0.75 mol

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl in 250.0 mL = Moles x Molar mass

= 0.75 mol x 58.44 g/mol

= 43.83 g

Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.

Explanation:

6 0

3 years ago

If 00810 mol neon gas at the particular temperature and pressure occupies a volume of 214 mL ehat volume would 0.00684 mol neon

Grace [21]

Answer:

$V_2=181mL$

Explanation:

Hello,

In this case, Avogadro's relationship allows us to relate the moles and the volume of a gas at an initial condition and an a final one as shown below:

$\frac{n_1}{V_1}=\frac{n_2}{V_2}$

Thus, the volume that 0.00684 mol of neon the same pressure and temperature is computed below as required:

$V_2=\frac{V_1*n_2}{n_1}=\frac{214mL*0.00684mol}{0.00810mol} \\\\V_2=181mL$

Best regards.

6 0

3 years ago

2. You have 200g or a solution that contains 30g of hydrochloric acid (HCI),

alex41 [277]

Answer:

the percentage of your solution that made up of HCI acid is 15%

Explanation:

The computation of the percentage of your solution that made up of HCI acid is given below:

Given that

There is 200g or a solution that have 0 g of hydrochloric acid (HCI)

Based on the above information

The percentage is

= 30g ÷ 200g

= 15%

Hence, the percentage of your solution that made up of HCI acid is 15%

7 0

3 years ago

Which property increases as you move down a column in the periodic table?

777dan777 [17]

Answer:

I think it's c have a good day

7 0

3 years ago

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