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aniked [119]
3 years ago
10

The Moon’s appearance changes during its ________ around Earth. These changes are called ____________________.

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

Answer:

The Moon’s appearance changes during its orbit around Earth. These changes are called phases.

Explanation:

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Which of the following is not present in an atom?<br> Electron<br> Element<br> Neutron<br> Proton
Licemer1 [7]

Answer:

an element is not in an atom

Explanation:

because the only things in a atom are electrons neutrons and protons

4 0
3 years ago
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Which of the following is true for balancing equations?
algol [13]

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

5 0
3 years ago
1. Explain the two processes that keep atmospheric oxygen and carbon dioxide at stable levels?
lesya [120]

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3 years ago
One difference between molecular formula and molecular weight.​
jek_recluse [69]

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3 0
2 years ago
A reaction that occurs in the internal combustion engine is n2(g) + o2(g) ⇌ 2 no(g) (a) calculate δh o and δs o for the reaction
jekas [21]
1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
7 0
2 years ago
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