Question

If 00810 mol neon gas at the particular temperature and pressure occupies a volume of 214 mL ehat volume would 0.00684 mol neon gas occupy under the same conditions

Answer 1

Answer:

$V_2=181mL$

Explanation:

Hello,

In this case, Avogadro's relationship allows us to relate the moles and the volume of a gas at an initial condition and an a final one as shown below:

$\frac{n_1}{V_1}=\frac{n_2}{V_2}$

Thus, the volume that 0.00684 mol of neon the same pressure and temperature is computed below as required:

$V_2=\frac{V_1*n_2}{n_1}=\frac{214mL*0.00684mol}{0.00810mol} \\\\V_2=181mL$

Best regards.