Actual yield of Fe2(So4)3 = 18.5g
2FePo4 + 3Na2SO4 -> Fe2(SO4)3 + 2Na3PO4
Mole of FePO4 = mass of it / its molar mass =
25 g / (55.8 + 31 + 16*4) = 0.166 mol
every 2 mole of FePO4 will form 1 mole of Fe2(SO4)3
Mole of Fe2(SO4)3 produced = 0.166 / 2 = 0.0829 mol
0.0829 * (55.8*2 + 3*(32.1+ 16*4)) = 33.148 g of Fe2(SO4)3
18.5 / 33.148 * 100 = 55.8%
A.) desertification is when you remove all the trees and most of the plant life in an ares
The answer would be the first one.
Answer:
for combustion of naphthalene is -5164 kJ/mol
Explanation:
where, C refers heat capacity and 
refers change in temperature.
Here, 
So, 
is generally expressed in terms of per mole unit of reactant. Also, should be negative as it is an exothermic reaction (temperature increases).
Molar mass of naphthalene is 128.17 g/mol
So, 1.025 g of naphthalene = 
of naphthalene
= 0.007997 moles of naphthalene
