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slega [8]
3 years ago
6

Amy and her father are playing with a squeaky toy. Amy's father is squeezing the toy in front of Amy. Amy is very excited and re

aches for the toy. Amy's father, however, quickly hides the toy behind his back. At this point, Amy turns away from her father and begins to look at the ladybug design on her dress. Amy is probably approximately what age?
Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0

Answer: 1 year old

Step-by-step explanation:

JulsSmile [24]3 years ago
5 0

Answer:

Amy is 6 moths to 1 year

Step-by-step explanation:

Amy is probably around 6 moths to a year old and the fact that she immediately turns attention to something else tells a lot that she is still too young and hasn't attained much development as a child who has reached 2 years or more.

The reason for her focusing attention somewhere else is due to the fact that her brain hasn't developed much and she doesn't even recall what happened a couple of seconds ago which is one of the characteristics of kids under her age,but with time and she will develop and remember more.

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In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the
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Answer:

P(t) = 5100e^{0.0039t}

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

P(t) = P(0)e^{rt}

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that P(0) = 5100

So

P(t) = 5100e^{rt}

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that P(5) = 5200.

We use this to find r.

P(t) = 5100e^{rt}

5200 = 5100e^{5r}

e^{5r} = \frac{52}{51}

\ln{e^{5r}} = \ln{\frac{52}{51}}

5r = \ln{\frac{52}{51}}

r = \frac{\ln{\frac{52}{51}}}{5}

r = 0.0039

So the equation for the moose population is:

P(t) = 5100e^{0.0039t}

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Step-by-step explanation:

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