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slega [8]
3 years ago
6

Amy and her father are playing with a squeaky toy. Amy's father is squeezing the toy in front of Amy. Amy is very excited and re

aches for the toy. Amy's father, however, quickly hides the toy behind his back. At this point, Amy turns away from her father and begins to look at the ladybug design on her dress. Amy is probably approximately what age?
Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0

Answer: 1 year old

Step-by-step explanation:

JulsSmile [24]3 years ago
5 0

Answer:

Amy is 6 moths to 1 year

Step-by-step explanation:

Amy is probably around 6 moths to a year old and the fact that she immediately turns attention to something else tells a lot that she is still too young and hasn't attained much development as a child who has reached 2 years or more.

The reason for her focusing attention somewhere else is due to the fact that her brain hasn't developed much and she doesn't even recall what happened a couple of seconds ago which is one of the characteristics of kids under her age,but with time and she will develop and remember more.

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How many cups are in 10 quarts?
Neporo4naja [7]
40 us customary cups
4 0
4 years ago
When the sun is at a certain angle in the sky, a 100 foot building will cast a 25 foot shadow. How y’all is a person if he casts
uysha [10]

Answer:

  6 ft

Step-by-step explanation:

The building height of 100 ft is 4 times the shadow length of 25 ft. At the same ratio, the person's height is 4 times the 1.5 ft shadow length, so is ...

  4 × (1.5 ft) = 6.0 ft

The person is 6 ft tall.

4 0
3 years ago
What is the area of ABC?
notsponge [240]

Let D be the Intersection of Height of the Triangle and Base of the Triangle BC

From the Figure, We can notice that Triangle ADB is a Right angled Triangle.

We know that, In a Right angled Triangle :

\bigstar  (Hypotenuse)² = (First Leg)² + (Second leg)²

In Triangle, ADB : AB is the Hypotenuse, AD is the First leg and BD is the Second leg

Given : AB = 15 and BD = 9

Substituting the values, We get :

:\implies  (15)² = (AD)² + (9)²

:\implies  225 = (AD)² + 81

:\implies  (AD)² = 225 - 81

:\implies  (AD)² = 144

:\implies  (AD)² = (12)²

:\implies  AD = 12

We know that, In a Right angled Triangle :

\bigstar\;\;\boxed{\mathsf{Tan\theta = \dfrac{Opposite\;Side}{Adjacent\;Side}}}

Now, Consider Triangle ADC : With respect to 45° Angle, AD is the Opposite Side and DC is the Adjacent Side

:\implies \mathsf{In\;Triangle\;ADC,\;Tan45^{\circ} = \dfrac{AD}{DC}}

\mathsf{:\implies 1 = \dfrac{12}{DC}}

:\implies  DC = 12

:\implies  Total Length of the Base (BC) = BD + DC

:\implies  Total Length of the Base (BC) = 9 + 12

:\implies Total Length of the Base (BC) = 21

We know that, Area of the Triangle is given by :

\bigstar\;\;\boxed{\mathsf{Area = \dfrac{1}{2} \times Base \times Height}}

In Triangle, ABC : AD is the Height and BC is the Base

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times BC \times AD}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times 21 \times 12}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = (21 \times 6)}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = 126}

7 0
4 years ago
Shannon is putting a fence around her garden, except where there is a gate that is 3 feet wide. One foot of the fence costs $43.
Anon25 [30]

x = the number of feet of fence

y = the total cost of the fence and gate

43x + 128 = y

[fence costs $43 per feet(x) plus the cost of the gate(128) equals the total cost of the fence and gate(y)]

7 0
4 years ago
A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea
marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that n = 11

Each question has five choices.

This means that p = \frac{1}{5} = 0.2

(a) Find P (6)

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859

P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362

P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953

P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389

Then

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611

P(More than 3) = 0.1611

8 0
4 years ago
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