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3 years ago

What is the vertex of x^2

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Answer:

The vertex is (0,0)

Step-by-step explanation:

To find the x coordinate of the vertex

x = -b/2a where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)

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iren2701 [21]

Answer:

so, it's 0.1x35=3.5

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2 years ago

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Mrs. Pascal has a candy jar that contains 5 Jolly Ranchers and 13 jawbreakers. Solve each of the following problems and explain

UkoKoshka [18]

Answer:

Step-by-step explanation:

The ratio is 5:13 and the total number of candy is 18. If the total amount of candy increased by 40x then both candy values would increase by 40x. There are 200 Jolly ranchers and 520 jawbreakers.

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2 years ago

Find the value of unknown angle

trapecia [35]

Answer:

x + 50° + 70° = 180°

or, x + 120° = 180°

or, x = 180° - 120°

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Step-by-step explanation:

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3 years ago

For one toss of a certain coin, the probability that the outcome is heads is 0.6. If this coin is tossed 5 times, which of the f

pishuonlain [190]

Answer:

The probability is 0.33696

Step-by-step explanation:

The probability that the outcome will be heads x times is calculated using the following equation:

$P(x) = nCx*p^{x} *(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

This apply for variables that follows a binomial distribution. In which we have n independent and identical events with two possibles results: success and fail with a probability p and 1-p respectively.

So, In this case, n is equal to 5, and p is equal to 0.6 because we are going to call success the event in which the outcome of the coin is head.

Then, the probability that the outcome will be heads at least 4 times is calculated as:

P = P(4) + P(5)

Where P(4) is:

$P(4) = 5C4*0.6^{4} *(1-0.6)^{5-4}$

P(4)=0.2592

And P(5) is:

$P(5) = 5C5*0.6^{5} *(1-0.6)^{5-5}$

P(4)=0.07776

Finally, the probability is:

P = 0.2592 + 0.07776

P = 0.33696

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3 years ago

How many months are in 59 days???

noname [10]

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