What is the vertex of x^2
1 answer:
Answer:
The vertex is (0,0)
Step-by-step explanation:
To find the x coordinate of the vertex
x = -b/2a where ax^2 +bx +c
a=1 b=0 c=0
x = -0/2(1) = 0
The y value is found by substituting into the equation
y = (0)^2 =0
The vertex is (0,0)
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