Answer:
The domain and the range of the function are, respectively:
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Step-by-step explanation:
Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
A(r)=3.14r^2, when r=5
A(5)=3.14(5^2)
A(5)=3.14(25)
A(5)=78.5 u^2
f(x)= -x^2 + x^-1
f(-2)= - (-2)^2 + (-2)^-1 = -4 - 1/2 = -9/2
f(-1)= - (-1)^2 + (-1)^-1 = -1 -1 = -2
f(1) = - (1)^2 + (1)^-1 = -1 +1 = 0
The range is { -9/2, -2, 0}
Answer:
the radius
Step-by-step explanation:
the correct answer is the radius