Answer:
720 ways
Step-by-step explanation:
Generally, combination is expressed as;

The question consists of 9 multiple-choice questions and examinee must answer 7 of the multiple-choice questions.
⇒ ⁹C₇ 

= 36
The question consists of 6 open-ended problems and examinee must answer 3 of the open-ended problems.
⇒ ⁶C₃ 

= 20
Combining the two combinations to determine the number of ways the questions and problems be chosen if an examinee must answer 7 of the multiple-choice questions and 3 of the open-ended problem.
⁹C₇ × ⁶C₃
= 36 × 20
= 720 ways
812-536=275
275 more people attended the play.
I think it’s A hope this helps
Answer:

Step-by-step explanation:
Factor by grouping:
'-5' is a common factor.
Factoring out '-5'....

Hope this helps.
Hello :
<span>x^3-3x^2+2x=0
x(x²-3x+2) = 0
x(x-1)(x-2) = 0
x = 0 or x-1 = 0 or x-2= 0
x = 0 or x = 1 or x = 2
two </span><span>roots are greater than 1/2 : 1 and 2</span>