Convert 5 over 8 to a decimal and tell whether it terminates or repeats.

Kipish [7]

Step-by-step explanation:

when we simplify the original expression, we can combine the y parts and the x parts - remember multiplying with exponents means adding the exponents.

so,

y^-8 × y^3 = y^(-8 + 3) = y^-5

x^0 × x^-2 = x^(0 - 2) = x^-2

therefore, the main expression is actually

y^-5 × x^-2

now also remember, a negative exponent means 1/...

so, this is

1/(y⁵) × 1/(x²) = 1/(y⁵x²)

now, let's have a look at the answer options and compare with our results above :

the first one is wrong.

the second one is correct.

the third one is correct.

the fourth, fifth and sixth ones are wrong.

7 0

3 years ago

if you multiply me by 2, I become a number greater than 20 and less than 40. if you multiple me by 6 I end in 8

snow_lady [41]

Lets say you are x
20<2x<40
therefore x has to be greater than 10, but less than 20
6x=_8
the only numbers between 10 and 20 that works with this equation are 13 and 18
(6x13=78 and 6x18=108)

5 0

3 years ago

Read 2 more answers

How do you write <br> 16<br> _<br> 8<br> as a percentage?

Sav [38]

I think its 200%

Best Of Luck!!!!
:D

7 0

4 years ago

The repairs bill on your car includes $355 for parts $146 for labor and a sales tax of $40 what is the total amount you owed

marissa [1.9K]

Answer:

$541

Step-by-step explanation:

Given:

The repair bill includes $355 for parts $146 for labor and a sales tax of $40

Question asked :

what is the total amount we owed = ?

Solution:

Total cost of parts to repair = $355

Total cost of labor = $146

Sales tax =$40

By adding all the cost:

Total cost of repair = $355 + $146 + $40

= $541

Therefore, total amount we have to pay = $541

7 0

3 years ago

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

3 years ago