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Marat540 [252]
1 year ago
10

If w represents the width of the tree house, which inequality could be used to determine what lengths would make the area of the

base of the tree house greater than 293 square inches?
Mathematics
1 answer:
Doss [256]1 year ago
7 0

An inequality which could be used to determine the lengths that would make the area of the rectangular base of the tree house greater than 293 square inches is W² + 7W > 293.

<h3>How to calculate the area of a rectangle?</h3>

Mathematically, the area of a rectangle can be calculated by using this formula;

A = LW

Where:

  • A is the area of a rectangle.
  • L is the length of a rectangle.
  • W is the width of a rectangle.

For the length and area of the rectangular base, we have:

L = W + 7

A > 293

Substituting the given parameters into the formula, we have;

L × W > 293

(W + 7) × W > 293

W² + 7W > 293

Read more on area of a rectangle here: brainly.com/question/25292087

#SPJ4

Complete Question:

Adam built a tree house with a rectangular base. The length of the base is 7 inches more than its width. If w represents the width of the tree house, which inequality could be used to determine what lengths would make the area of the base of the tree house greater than 293 square inches?

W + 7 > 293

202 + 286 > 2,051

w² + 7w > 293

12 + 293 > 293

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6 0
3 years ago
4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (
Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0
3 years ago
A farmer has both pigs and chickens on his farm there are 78 fee and 27 heads how many pigs and how many chickens are there
Andre45 [30]
Assuming health non-mutated animals:
Feet = 4*Pigs + 2*Chickens
Heads = Pigs + Chickens

By back substitution:
78 = 4*(27-Chickens) + 2*Chickens
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Then:
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To check:
Feet = 4*Pigs + 2*Chickens
78 = 4*12 + 2*15
78 = 48 + 30
78 = 78 CHECKS
6 0
3 years ago
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