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3 years ago

3^4 + 2 • 5 = (input whole numbers only.) (please leave explanation)

1 answer:

4 0

Answer = 91
So first use the order of operations: parentheses, exponents, multiply/divide, add/subtract to do 3^4 (this is an exponent) first which is 81. Then do the multiplication, 2•5, which equals 10. Finally add the 81+10 to get 91 as your final answer. Hope that helps :)

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What mathematical pattern can be seen in a perfect square trinomial and how is the pattern used to factor the trinomi

Shtirlitz [24]

(a ± b)² = a² ± 2ab + b² . . . . . . . (signs match)

The middle term is twice the product of the roots of the other two terms. This tells you the terms of the binomial are the square roots of the end terms.

The sign in the binomial will match the sign of the "2ab" term. The order of terms in the binomial doesn't matter. (a±b)² = (b±a)² when signs match.

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3 years ago

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kkurt [141]

Answer:

Step-by-step explanation:

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3 years ago

Simplify the expression. (7x + 3) + (4x - 1) - (2x + 4)

Crazy boy [7]

Answer:

9x -2

Step-by-step explanation:

(7x + 3) + (4x - 1) - (2x + 4)

Distribute the minus sign

(7x + 3) + (4x - 1) - 2x - 4

Combine like terms

7x+4x-2x +3 -1-4

9x -2

3 0

3 years ago

Jen wants to tile the floor of her kitchen. The floor is rectangular and measures 12 feet by 8 feet. If it costs $2.50 per squar

Keith_Richards [23]

I hope this helps you

8 0

3 years ago

Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h

Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

$T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182$

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

$T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148$

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

$T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378$

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

$T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899$

So 2899 possible ways.

4 0

3 years ago