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svetlana [45]
3 years ago
12

If Matrix A has dimensions 1x4 and Matrix B has dimensions 3x4, can these be multiplied?

Mathematics
2 answers:
Inga [223]3 years ago
6 0
\bf A=
\begin{bmatrix}
\square &\square &\square &\square 
\end{bmatrix}\qquad \qquad 
B=
\begin{bmatrix}
\square &\square &\square &\square \\
\square &\square &\square &\square \\
\square &\square &\square &\square \\
\end{bmatrix}

notice above, the matrix A has 1 row 4 columns, a 1x4,
and the B matrix has 3 rows and 4 columns, 3x4.

since B has only 3 rows, not 4, no dice.
Kipish [7]3 years ago
3 0
Answer: No. You cannot multiply the matrices in any order. A*B is not defined. Also, B*A is not defined.

------------------------------------------------------------------------

Explanation: 

Matrix A has 1 row, and 4 columns. 
Matrix B has 3 rows, and 4 columns

In order for A*B to be possible, A has to have the same number as columns as B has rows. In other words, the inner dimensions have to match up. The '4' in '1x4' needs to match up with the '3' in the '3x4'. This match doesn't happen. 

The same story happens with B*A, just things have been flipped. 

B has 3 rows, 4 columns
A has 1 row, 4 columns

The "4 columns" of B does not match with "1 row" of A. 
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Sienna has 5 3/4 pounds of grapes. She eats 1/8 pound and gives 2 1/2 pounds to her brother. How many pounds of grapes does Sien
miskamm [114]

The pounds of grapes left with seinna is 3.125 or \frac{25}{8} pounds

<h3><u>Solution:</u></h3>

Given that Sienna has 5\frac{3}{4} pounds of grapes

She eats \frac{1}{8} pound and gives 2\frac{1}{2} pounds to her brother

<em><u>To find: pounds of grapes left with seinna</u></em>

We can find the pounds of grapes left with seinna by subtracting the pounds of grapes she ate and pounds of grapes she gave to brother from the total pounds of grapes she had

Pounds of grapes left with seinna = total pounds of grapes - pounds of grapes she ate - pounds of grapes she gave to brother

\text {total pounds of grapes }=5 \frac{3}{4}=\frac{4 \times 5+3}{4}=\frac{23}{4}

\text {pounds of grapes she ate }=\frac{1}{8}

\text {pounds of grapes she gave to brother }=2 \frac{1}{2}=\frac{2 \times 2+1}{2}=\frac{5}{2}

<em><u>Substituting the values we get,</u></em>

\text {Pounds of grapes left with seinna }=\frac{23}{4}-\frac{1}{8}-\frac{5}{2}

\text { Pounds of grapes left with seinna }=5.75-0.125-2.5=3.125

Thus the pounds of grapes left with seinna is 3.125 or \frac{25}{8} pounds

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Answer:

     

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