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Semmy [17]
3 years ago
9

Vertex and axis of symmetry f(x)=2x^2-16x-17 PLEASE HELP

Mathematics
1 answer:
Law Incorporation [45]3 years ago
8 0
The vertex is at (4, -49) and the axis of symmetry is at x= 4.

To find the vertex of this equation, use this method: ( \frac{-b}{2a})

a=2
b=-16

This will help get your x value and the axis of symmetry. To find the y value of the vertex, insert the x value, 4 to get your y value, -49.
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