3 years ago

Vertex and axis of symmetry f(x)=2x^2-16x-17 PLEASE HELP

1 answer:

8 0

The vertex is at (4, -49) and the axis of symmetry is at x= 4.

To find the vertex of this equation, use this method: $( \frac{-b}{2a})$

a=2
b=-16

This will help get your x value and the axis of symmetry. To find the y value of the vertex, insert the x value, 4 to get your y value, -49.

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