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Karolina [17]
3 years ago
7

A kite is flying on 39 feet of string. How high is it above the ground if it’s height is 22 feet more than the horizons distance

from the person flying it. Assume that the string is being held at ground level.
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Answer:

about 36.3 feet

Step-by-step explanation:

Let x represent the height of the kite in feet. Then (x-22) is the horizontal distance to the kite. The Pythagorean theorem tells you the string length is related to these distances by ...

... 39² = x² + (x-22)²

... 2x² -44x -1037 = 0 . . . . rearrange to standard form

Using the quadratic formula, the positive solution is ...

... x = (-b+√(b²-4ac))/(2a) . . . . for a=2, b=-44, c=-1037

... x = (44 + √((-44)² -4(2)(-1037)))/(2·2)

... x = 11 + √639.5 ≈ 36.288

The kite is about 36.3 feet above the ground.

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Two cars are 50 miles apart and driving towards each other. One car is driving at a speed of 30 miles per hour and the other car
ale4655 [162]

Answer:

40 minutes

Step-by-step explanation:

30x+45x=50

75x=50

x=.6667 hours or 40 minutes

check:

30 mph for 40 minutes=20 miles

45 mph for 40 minutes=30 miles

total=50 miles

3 0
3 years ago
A circular pond has a radius of 6 feet. What is the area of that pond?
serg [7]

Answer:

radius x radius x pi = area of circle

6 x 6 = 36

36 x 3.14 = 113.04

113.04

Hope this helps

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent to 7(p+2n)+n?
Illusion [34]
We actually need the choices but oh well, we can simpify and hopefuly it is one of the choices

remember the distributive property
a(b+c)=ab+ac
so

7(p+2n)+n
distribute first
7(p)+7(2n)+n
7p+14n+n
7p+15n is an equivilent expression
3 0
3 years ago
NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400
Ne4ueva [31]

Answer:

The test statistics is  t  =  -1.727

Step-by-step explanation:

From the question we are told that

The data given is  

   330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

 The population mean is  \mu  =  14400

    The  sample  size is  n =  16

  The  null hypothesis is  \mu \le  14400

    The  alternative hypothesis is  H_a  :  \mu > 14400

The sample mean is mathematically evaluated as

  \= x  =  \frac{\sum x_i}{n}

So

   \= x  =  \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}

=>  \= x = 10799.9

The  standard deviation is mathematically represented as

      \sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}

So

\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}}  \ ..

   ..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2  }{16}} \ ...

  \ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}

=>  \sigma  =  8340

  Generally the test statistic is mathematically represented as

  t =  \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }

t  =  -1.727

From the z-table  the p-value is  

     p-value  = P(Z > t) =  P(Z >  -1.727) =  0.95792

 From the values obtained we see that

        p-value  >  \alpha  so we fail to reject the null hypothesis

Which implies that the claim of the NarStor is wrong

5 0
3 years ago
Danielle wants to purchase some clothes. He has $75. He buys one leather jacket for $39 and 3 pairs of socks. Each pair of socks
butalik [34]

$12 each. $75 - $39 = $36. $36 divided by 3 = $12. Assuming he used all his money.


8 0
3 years ago
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