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Elanso [62]
4 years ago
12

A customer purchases a camera for $76.27. If the customer gives you $100, how much change should you give them back?

Mathematics
2 answers:
devlian [24]4 years ago
6 0
That's basic arithmetic. the equation on paper would be 100.00. The answer would be 27.73.                                                               - 76.27

P.S. Just use a calculator next time.
andreev551 [17]4 years ago
5 0
£100 - £76.27
£23.73 amount in change would be given back
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The expression 1500(1.07)^t represents the value of a $1500 investment that earns 7% interest per year, compounded annually for
fomenos
Total = Principal * (1 + rate) ^ years
Total = 1,500 * (1.07) ^ 2
Total = 1,717.35


6 0
3 years ago
Use the Parabola tool to graph the quadratic function.
Kitty [74]

Step-by-step explanation:

f(x) = 2x²+8x+10

vertex point :

x = -8/2(2)= -8/4

=> x = -2 <= this is a symetry axis

f(-2)= 2(-2)²+8(-2)+10=8-16+10=2

the vertex point : (-2, 2)

intercept with y-axis :

f(0) = 0+0+10 = 10

the point : (0, 10)

the drawing as attached

3 0
3 years ago
The ratio of destroyers to battleships in the navy is 20:15. If the total number of boats is 105, how many battleships are there
Elina [12.6K]

Answer:

45

Step-by-step explanation:

20:15 the ratio can be turned to a fraction

20/15

simplify

4/3

so now add the numerator and the denominator and get 7

then do 105/7=15

and then you do

4x15=60 (Destroyers)

3x15=45 (Battleships)

45 is your answer

7 0
3 years ago
If you invest $100,000 in an account earning 8% interest compounded annually, how long will it take until the account holds $300
Monica [59]

We have been given that you invest $100,000 in an account earning 8% interest compounded annually. We are asked to find the time it will take the amount to reach $300,000.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.  

8\%=\frac{8}{100}=0.08

300,000=100,000(1+\frac{0.08}{1})^{1\cdot t}

300,000=100,000(1.08)^{t}

\frac{300,000}{100,000}=\frac{100,000(1.08)^{t}}{100,000}

3=(1.08)^{t}

(1.08)^{t}=3

Let us take natural log on both sides of equation.

\text{ln}((1.08)^{t})=\text{ln}(3)

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

t\cdot \text{ln}(1.08)=\text{ln}(3)

\frac{t\cdot \text{ln}(1.08)}{\text{ln}(1.08)}=\frac{\text{ln}(3)}{\text{ln}(1.08)}

t=\frac{1.0986122886681097}{0.0769610411361283}

t=14.274914586

Upon rounding to nearest tenth of year, we will get:

t\approx 14.3

Therefore, it will take approximately 14.3 years until the account holds $300,000.

7 0
3 years ago
Which of the following represents represent linear functions?
denpristay [2]
Hey you can check this app called Conects it’s free it gives you the answers
4 0
3 years ago
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